Looking at his triangle, we see that is two 30-60-90 degree triangles. We had to divide this equilateral triangle. It has all three same sides, and three same angles. The hypotenuse is equaled to one, and one side is 1/2. Using the Pythagorean theorem, we will solve for "b". C should be rad3.
The pattern of this 30-60-90 triangle can be defined with any number, You start off by choosing a number, and plug it in for "n". You get 1n for a, and 2n for the hypotenuse. You will times two to rad3/2.
To get a 45-45-90 degree triangle by cutting a perfect square, slanted. This will divide two angle which equal 90 degrees. Both sides are 1, then you solve for the hypotenuse. C should be rad2.
As like the other triangle, any number can be used since it only gets the square bigger or smaller. Either way. the sides will be the same number. Since the sides can change number, we have to add "n" on each side in order to solve.
Reflections:
1. Something I never noticed about special right triangles is the fact that is related to the unit circle.
2. Being able to derive these patterns myself aids my learning by explaining the reasons we get specific answers to the problems given in this concept.
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