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Wednesday, March 5, 2014

WPP#12 Unit O Concept: 10: Solving Of Elevation and Depression Word Problems (able to define the longitute of a slant angle)

Saving Gwen Stacy



Gwen Stacy is captured my the evil Lizard. The lizard has Gwen Stacy on top of a building, where Spiderman cant reach. We have to help Spiderman find the length of each building to get to Gwen Stacy.
 

Spiderman starts on the first building,he has a little bit of web. This means he needs an exact height of the first building. The degree for the first triangle is 56 degrees, and the adjacent is 18 inches. Solve for the height, which is "x".

After he get to the second building, and has no choice but to jump off. This creates another height to figure out. The hypotenuse is 26 inches, and the degree is 32 degrees. Solve for "x".


In order to solve these triangles, we get to use SOH CAH TOA. Since the first triangle gives us the adjacent and "x" for opposite, we get to use Tangent. Tangent of 56=x/18. X will equal 26.69 inches.

Second Triangle has given us the Hypotenuse, 26inches, and the opposite is "x". In this triangle, we will be using Sine(SOH). sine of 32=x/26. This should equal 22.048 inches.
 

Tuesday, March 4, 2014

I/D#2 Unit O Concept 7-8: How can we derive special right triangles?



 
 
 
Looking at his triangle, we see that is two 30-60-90 degree triangles. We had to divide this equilateral triangle. It has all three same sides, and three same angles. The hypotenuse is equaled to one, and one side is 1/2. Using the Pythagorean theorem, we will solve for "b". C should be rad3.
 
The pattern of this 30-60-90 triangle can be defined with any number, You start off by choosing a number, and plug it in for "n". You get 1n for a, and 2n for the hypotenuse. You will times two to rad3/2.
 
To get a 45-45-90 degree triangle by cutting a perfect square, slanted. This will divide two angle which equal 90 degrees. Both sides are 1, then you solve for the hypotenuse. C should be rad2.
 
As like the other triangle, any number can be used since it only gets the square bigger or smaller. Either way. the sides will be the same number. Since the sides can change number, we have to add "n" on each side in order to solve.
 
Reflections:
 
1. Something I never noticed about special right triangles is the fact that is related to the unit circle.
2. Being able to derive these patterns myself aids my learning by explaining the reasons we get specific answers to the problems given in this concept.


Friday, February 21, 2014

I/D#1: Unit N Concept 7-9: knowing all degrees and radians

 

Before starting Concept 7-9 in Unit N, we worked on an activity that derives the Unit Circle. This means we got extra help for us to understand the Unit Circle. This activity will help us understand how to get the radians on the unit circle. This activity contained three triangles, and we had to label and draw coordinates.

First step: Label according to the rules of Special Right Triangles: You could have just googled  "rules of Special Right Triangles" and would have gotten the hypotenuse is 2x, and one leg is x, the other leg is x radical 3.
Second Step: Simplify the three sides of the triangle fairly in a way such that hypotenuse equals 1: This meant that the hypotenuse has to equal one. In order to get 2x to equal one, is dividing it by 2x. This meant to divide everything in 2x, since it said simplify fairly. Hypotenuse=1, leg1= 1/2, and leg2=radical 3/2.
Third step: Label the hypotenuse "r": The hypotenuse is labeled "r"
Fourth Step: Label the horizontal value "x": Leg 2 is labeled "x"
Fifth Step: Label the vertical value "y": Leg1 is labeled "y"
Sixth step: Draw a coordinate plane for each triangle, with the origin being located at the labeled angle measured: You will have to draw a graph by the triangle, so the triangle will be on Quadrant 1.
Seventh Step: label all three vertices of each triangle as ordered pairs: Each corner of the triangle is a vertices, and has to be plotted. Also Labeled.

1. The 30 degree triangle is labeled and simplified, as the instruction has been explained. After you found the vertices, you will be able to find the radiant and vertices. This will always have a radical 3.
2. The 45 degree triangle is different than the 30 degree triangle. This will always have radical 2/2, or radical 2.
3. The 60 degree triangle is similar to the 30 degree triangle. This will have a radical 3, radical 3/3.

4. This activity helped me find my vertices of my unit circle, by using the special rights of triangle, and having the hypotenuse equal to 1. It also helped my find the radians of the unit circle. Before I will have not choice to just memorize the unit circle without knowing how to solve for them. This activity answered my question. If I forget the radian, now I know hoe to solve it.
5. If we place this triangle on a different quadrant, the signs will change. This is based on ASTC. When it lies on the first then all numbers will be positive. If it lies on Second then sine and cosecant will be positive, and the rest will be negative. Third quadrant, tangent and cotangent will be positive and the rest will be negative. Fourth quadrant, cosine, and secant will be positive and the rest will be negative.

1. The coolest thing I learned on this activity was finding out where did we get the different radians and vertices for the Unit Circle.
2. This activity will help me a lot by giving me a a second option on how to find the radian or degrees in my unit circle. In case I forget when I am trying to fill out by memory.
3. something I never realized before about special right triangle and the unit circle is that they are both derive information to me in order to find answers for concept 8 and 9.

Monday, February 10, 2014

RWA#1: Unit M Concept 5 : Graphing Ellipses given equation.

1. Mathematical Equation:
  • A curved line creating a close loop, where the total of the distance from the foci. The foci, creates the sum of the constant.
  • A set of all points such that the sum of the distance from two points is a constant.
2. Description:
  • Algebraically: (x-h)^2/a^2+(y-k)^2/b^2=1
  • Graphically:
  • key features: Standard Form- is the algebraically way to solve the ellipse.
Center: The center point will determine where the ellipse will be placed
                       2 vertices: These points are that will connect with center, and show what kind of ellipse it is
 
                       Major Axis: Depending on the minor, it will determine if it is skinny or fat.
                       Minor Axis: Depending on the major, it will determine if it is skinny or fat.
                       2foci: is the points that add up the two distance, which will have the same constant.
                       Eccentricity: measure how much the conic section deviates from being circular.
  • foci affects it by giving points that will add up the distance to a constant that id shared by the points.
3.
 
As you can see, this building has the ellipse shape in the center. The creator this building created a living space for someone, that gives a round shape to the house. This modern style creates a relaxing vision toward others eyes.
          Knowing that ellipse are used in the real world, brings excitement towards to math, and real world objects. The real world consists a lot of mathematical equations, and graphs.
 
4. Reference:



           

Monday, December 9, 2013

SP#6 Unit K Concept 10: Writing a repeating decimal as a rational number



We have been learning about finding terms in arithmetic, geometric, infinite, and finite sequences. In Unit K Concept 10, we learned about repeating decimals as rational numbers. I am showing you a more complex problem, since it has a whole number in the front. We will be using the geometric sequence formula. If you follow my steps you will find it pretty easy and understandable.

In the first step you will see my problem, which is 2.565656. Since the decimal is the 100th place, then "a sub 1" is 56/100. And the ratio is 1/100. The you will plug it in the Summation form. The Summation for will help you define the answers that you have found. Next is solving for the sum, using the geometric form. It will be simple division with fractions. That will get your sum.